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JordanRLS

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Everything posted by JordanRLS

  1. I've actually been active on here for quite a while but I just realised I never introduced myself! So hello, i'm 15 and i live in alton, hampshire. i've been playing bass for a few months now.
  2. After watching that i think i'll be slightly paranoid when attending gigs in places like that, scary stuff.
  3. I wont be using it for gigging, so the combination of what you guys have said and some of the reviews have made me decide on the laney, cheers
  4. Hey all, tomorrow i'm going to one of two music shops to buy either a fender rumble 60 or a laney RB3. what i need your help with is which one to go for? any experiences with them or an obvious preference?
  5. [quote name='AlanP2008' post='747381' date='Feb 16 2010, 04:02 PM']<more value than you asked for> Linear solid state amplifiers typically have (inside of them) unregulated +ve and -ve power supplies. The +ve and -ve output devices (bipolar or FET transistors) alternately progressively conduct to supply current to the load (the speakers) for each half of the signal waveform. If a given amplifier produces, say 100W into a 16ohm load, then *if* the power supplies maintained their voltages, it would produce 200W into an 8 ohm load. However, delivering that power actually causes most typical power supplies to "sag" their voltages, so as you halve the load, you actually get less than a doubling in power (ok, there are some other losses involved too - but sag is the main one) - so you might get 16ohm->100W, 8ohm->180W, 4ohm->320W, 2ohm->500W... A better (stiffer) power supply produces less sag, but costs more... But halving the load, in addition to (almost) doubling the power, also doubles the output current into the load. Most amplifiers are designed to supply sufficient current to drive down to a 4 ohm load, but some amplifiers are designed to deliver sufficient current to drive down to 2 ohms - this takes typically twice as many output devices as driving a 4 ohm load, so is more costly to manufacture. In addition, the power supply itself has to be able to deliver that additional current, and there will be more heat to get rid of, which again increases cost... The basic thing is W= V squared / R Watts = volts squared / resistance (in ohms) So as the load resistance is halved, the power output is doubled (provided the maximum output voltage remains the same - which it doesn't quite...) </more value than you asked for> I hope this helps Alan[/quote] Thanks very much, very helpful
  6. well, i am aware of the fact that there is a difference between 2, 4 and 8 ohm amps (i believe the lower it is, the higher wattage is passed?) I am just failing to understand why this difference occurs? confused!
  7. I may well be interested i this, but i'll be able to tell you for certain after Wednesday if it's still available then
  8. [quote name='Ou7shined' post='731251' date='Feb 1 2010, 12:30 AM']I buy turquoise basses.[/quote] love it
  9. The thing is, there's no chance of joining a band for a long while yet, what with gcse's. and i think i'm right in believing a 200watt amp would be well above my price range. but there's every chance i could be wrong about anything, which is why im asking
  10. forgot to mention, it will be used mostly for practice and maybe the occasional little jam with mates...
  11. Hey all, i've been playing bass for 5 months or so, and i feel it's time to move on from the little 10 watt amp my first bass came with, about time too! So, i have a very small budget (under £100 would be ideal) and am therefore looking into second hand. If possible i need as many recommendations for 2nd hand combos that would be worth the effort as i will be going around the local music shops hunting next week. thanks in advance.
  12. welcome from alton... not far away from you.
  13. hello all, I've been lurking on here for a while and figured it was about time to make an account. MY name's Jordan, im 15.. haven't been playing bass long but i'm loving it so far . so yeah.. hello!
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