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PhysicsQ&A LibraryAn electron has an initial velocity of 5.00×106 m/s in a uniform 2.00×105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.(a) What is the direction of the electric field? (b) How far does the electron travel before coming to rest? (c) How long does it take the electron to come to rest? (d) What is the electron’s velocity when it returns to its starting point?Start your trial now! First week only $4.99!*arrow_forward*

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An electron has an initial velocity of 5.00×10^{6} m/s in a uniform 2.00×10^{5} N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity.

(a) What is the direction of the electric field? (b) How far does the electron travel before coming to rest? (c) How long does it take the electron to come to rest? (d) What is the electron’s velocity when it returns to its starting point?

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